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Discover Python: Daily Questions for All Levels.
Welcome to our daily Python challenge! As lovers and enthusiasts of this amazing language, we have created a space where you can improve your skills and test your knowledge every day.
Each day, weβll post a new Python question, covering everything from basic concepts to advanced topics. Whether youβre a beginner eager to learn or an experienced programmer looking for a new challenge, our exercises are designed for everyone. Join us on this continuous learning journey.
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InfinitePy Newsletter - Your source for Python learning and inspiration.
Question β’ CEDB
November 01, 2024
What is the output for the Python code below?
class MagicToyBox(type): def __init__(cls, name, bases, attrs): cls._toy_counter = 0 super().__init__(name, bases, attrs) def __call__(cls, *args, **kwargs): cls._toy_counter += 1 return super().__call__(*args, **kwargs) class Toy(metaclass=MagicToyBox): def __init__(self, fun_shape): self.fun_shape = fun_shape toy1 = Toy("π") toy2 = Toy("π»") toy3 = Toy("π¦") print(f"How many toys in the box? {Toy._toy_counter}")
Answer
3
Let's analyze the code step by step:
# Import the necessary libraries if needed (in this case, none are needed). # Define a metaclass called MagicToyBox using Python's built-in 'type' metaclass. # A metaclass in Python is a class of a class that defines how classes behave. class MagicToyBox(type): # The __init__ method of the metaclass is similar to an ordinary class's __init__ method. # It initializes the metaclass itself and is called when a new class using this metaclass is created. def __init__(cls, name, bases, attrs): # 'cls' refers to the newly created class using this metaclass. # Initialize a class attribute _toy_counter to zero to count how many instances of the class are created. cls._toy_counter = 0 # Call the base class (type)'s __init__ method to complete the initialization. super().__init__(name, bases, attrs) # The __call__ method is invoked when an instance of a class (that uses MagicToyBox as a metaclass) is created. def __call__(cls, *args, **kwargs): # Increment the toy counter every time a new toy instance is created. cls._toy_counter += 1 # Call the parent class's __call__ method to proceed with creating the new instance. return super().__call__(*args, **kwargs) # Define a class called Toy that uses MagicToyBox as its metaclass. # The line "metaclass=MagicToyBox" means any class behavior defined in the metaclass will apply to Toy. class Toy(metaclass=MagicToyBox): # The __init__ method is called whenever an instance of Toy is created. def __init__(self, fun_shape): # 'fun_shape' is a parameter that represents the shape of the toy, such as a car, bear, or dinosaur. # It is stored as an instance attribute, meaning each Toy instance can have a different fun_shape. self.fun_shape = fun_shape # Create different instances of the Toy class, passing different emoji shapes as arguments. toy1 = Toy("π") # An instance of Toy representing a toy car. toy2 = Toy("π»") # An instance of Toy representing a toy bear. toy3 = Toy("π¦") # An instance of Toy representing a toy dinosaur. # Output the total number of Toy instances created. The _toy_counter class attribute keeps track of this. # By accessing Toy._toy_counter, we get the total count of toy instances created so far. print(f"How many toys in the box? {Toy._toy_counter}")
Question β’ 86C9
October 31, 2024
What is the output for the Python code below?
dict1 = {"a": 1, "b": 2} dict2 = {"a": 1, "b": 3} print(dict1 != dict2)
Answer
True
Let's analyze the code step by step:
# Define the first dictionary named `dict1` # This dictionary has two key-value pairs: # Key "a" with value 1 # Key "b" with value 2 dict1 = {"a": 1, "b": 2} # Define the second dictionary named `dict2` # This dictionary also has two key-value pairs: # Key "a" with value 1 # Key "b" with a different value, 3 dict2 = {"a": 1, "b": 3} # Use the inequality operator (!=) to compare dict1 and dict2 # The `!=` operator checks if the two dictionaries are not equal # Two dictionaries are considered equal if they have the same key-value pairs # Since dict1 and dict2 differ in the value associated with the key "b", they are not equal result = dict1 != dict2 # Print the result of the comparison # Since dict1 and dict2 have different values for key "b" (2 in dict1, 3 in dict2), # the result of the comparison is True print(result) # Output: True
Question β’ 4AEB
October 30, 2024
What is the output for the Python code below?
x = ['π₯¦', 'π₯', 'π½'] y = x[:] y.append('π ') print(x)
Answer
['π₯¦', 'π₯', 'π½']
Let's analyze the code step by step:
# Create a list 'x' containing three emoji elements representing vegetables. x = ['π₯¦', 'π₯', 'π½'] # Create a new list 'y' by slicing the entire list 'x'. # The colon (:) slice operation creates a shallow copy of 'x'. # This means 'y' is a new list with the same elements as 'x', # but 'y' and 'x' are separate objects in memory. y = x[:] # Append the emoji 'π ' (representing a tomato) to the end of the list 'y'. # This modifies the list 'y' by adding one more element to it. y.append('π ') # Print out the original list 'x'. # Even though we modified 'y', the list 'x' remains unchanged because # 'y' is a separate copy due to the slicing operation used earlier. print(x)
Question β’ E5F1
October 29, 2024
What is the output for the Python code below?
from collections import deque my_deque = deque(['a', 'b', 'c']) my_deque.append('d') my_deque.appendleft('z') my_deque.pop() print(list(my_deque))
Answer
['z', 'a', 'b', 'c']
Let's analyze the code step by step:
# Importing the deque class from the collections module. # The collections module provides alternatives to Pythonβs general-purpose built-in containers like dict, list, set, and tuple. from collections import deque # Creating a deque (double-ended queue) object named my_deque with an initial list ['a', 'b', 'c']. # A deque allows for fast and efficient appends and pops from both ends. my_deque = deque(['a', 'b', 'c']) # Append 'd' to the right end of the deque. # After this operation, my_deque becomes: deque(['a', 'b', 'c', 'd']) my_deque.append('d') # Append 'z' to the left end of the deque. # After this operation, my_deque becomes: deque(['z', 'a', 'b', 'c', 'd']) my_deque.appendleft('z') # Pop an element from the right end of the deque and return it. # The element 'd' will be removed. # After this operation, my_deque becomes: deque(['z', 'a', 'b', 'c']) my_deque.pop() # Convert the deque to a list and print it. # The result will be: ['z', 'a', 'b', 'c'] # Lists are commonly used in Python, and converting a deque to a list can be helpful for certain operations. print(list(my_deque))
Question β’ B4BA
October 28, 2024
What is the output for the Python code below?
def check_numbers(nums): for num in nums: if num < 0: print("Found a negative number:", num) break else: print("All numbers are non-negative.") nums = [1, 2, 3, 4] check_numbers(nums)
Answer
All numbers are non-negative.
Let's analyze the code step by step:
# Define a function named 'check_numbers' which takes one parameter 'nums' # 'nums' should be a list of numbers. def check_numbers(nums): # Start a for-loop to iterate over each element (number) in the 'nums' list. for num in nums: # Check if the current number 'num' is less than 0 (negative). if num < 0: # If a negative number is found, print a message with the negative number. print("Found a negative number:", num) # Break out of the loop since we found a negative number; no need to check further. break # The else block associated with a for-loop only executes if the loop completes # without hitting a break statement. This means no negative numbers were found. else: # Since the loop completed without finding a negative number, print a message # indicating all numbers are non-negative. print("All numbers are non-negative.") # Create a list 'nums' with positive numbers. nums = [1, 2, 3, 4] # Call the 'check_numbers' function with the 'nums' list. # This will check each number in the list for negativity and respond accordingly. check_numbers(nums)